Question

The vertices of a triangle are located at the points A(-2,-1) , B (1,3) and C (2,-4). The triangle is translated 2 units right and 3 units up. What are the coordinates of the vertices of triangle A'B'C'?

Answer 1

Given the coordinates of the parent function

`\begin{gathered} A\rightarrow(-2,-1) \\ B\rightarrow(1,3) \\ C\rightarrow(2,-4) \end{gathered}`

Then, the triangle is translated 2 units right and 3 units up. This will then be

`\begin{gathered} A^(\prime)\rightarrow(-2+2,-1+3)=(0,2) \\ B^(\prime)\rightarrow(1+2,3+3)=(3,6) \\ C^(\prime)\rightarrow(2+2,-4+3)=(4,-1) \end{gathered}`

Hence, the coordinates of the vertices of triangle A'B'C' are

`A^(\prime)(0,2),B^(\prime)(3,6),C^(\prime)(4,-1)`