61.8k views
4 votes
Find sect 。A)B)op回?2121

User Retozi
by
7.8k points

1 Answer

3 votes

We will operate as follows:


x=\frac{\sqrt[]{21}}{5}
y=(2)/(5)

Then:


r^2=(\frac{\sqrt[]{21}}{5})^2+((2)/(5))^2\Rightarrow r=1

Then we calculate cosine in order to determine the secant:


\cos (\theta)=(x)/(r)\Rightarrow\cos (\theta)=\frac{\frac{\sqrt[]{21}}{5}}{1}\Rightarrow\cos (\theta)=\frac{\sqrt[]{21}}{5}

Now, the secant:


\sec (\theta)=(1)/(\cos(\theta))\Rightarrow\sec (\theta)=\frac{1}{\frac{\sqrt[]{21}}{5}}
\Rightarrow\sec (\theta)=\frac{5}{\sqrt[]{21}}=\frac{5\sqrt[]{21}}{21}

So, the soluton would be option B.

User Jjlema
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories