Given:
Function 1 is given in the graph.
Function 2 is,

To find:
The function has a larger maximum value.
Step-by-step explanation:
From the graph,
We know that the maximum value of the function is the highest point of the function.
For the function 1, the maximum value is 1 at x = 4.
For the function 2,
Differentiating with respect to x, we get

Equate it with zero, and we get

Substituting x = 1 in function 2.

So, the maximum value is -14 at x = 1.
Then, comparing functions 1 and 2 we get,
Function 1 has the larger maximum value at (4, 1).
Final answer:
Function 1 has the larger maximum value at (4, 1).