Question

A circuit with a battery, a 5 Ω resistor, a 14 Ω resistor, and a 21 Ω resistor in parallel. The total voltage is the system is 4.7 V. What is the current through the 5 Ω resistor?

Answer 1

0.94A

Step-by-step explanation

We have the following circuit,

All the resistors of the circuit are connected in parallel, which means that they all have the same voltage drop. Since they are connected in parallel with the voltage source, the voltage drop across all of them is 4.7V.

Using Ohm's law, we can find the current through the 5Ω resistor,

`I_(5\Omega)=(V_(5\Omega))/(R_(5\Omega))=(4.7V)/(5\Omega)=0.94A`

Hence, the current through the 5Ω resistor is 0.94A.