Question

2/3 + 3k/4 = 71/12. How do I do this?

Answer 1

We want to solve the following equation:

`(2)/(3)\text{ + }(3k)/(4)\text{ = }(71)/(12)`

that is equivalent to :

`(2)/(3)-(2)/(3)\text{ + }(3k)/(4)\text{ = }(71)/(12)\text{ - }(2)/(3)`

that is

`\text{ }(3k)/(4)\text{ = }(71)/(12)\text{ - }(2)/(3)`

now, we will solve the right part of the equation:

`\text{ }(3k)/(4)\text{ = }(71)/(12)\text{ - }(2x4)/(3x4)\text{ = }(71)/(12)\text{ - }(8)/(12)\text{ = }(71-8)/(12)\text{ = }(63)/(12)`

that is :

`\text{ }(3k)/(4)\text{ = }(63)/(12)`

Now, we resolve for k:

`\text{ k = }\frac{63\text{ x 4}}{12\text{ x 3}}\text{ = }(252)/(36)\text{ = 7}`

we can conclude that :

k = 7