Question

Can you teach me how to do logarithms? ------equation---log500−log1/2 =

Answer 1

To answer this question we will use the following property of logarithms:

`\log a-\log b=\log (a)/(b)\text{.}`

Therefore:

`\log 500-\log (1)/(2)=\log (500)/((1)/(2))\text{.}`

Simplifying the above result we get:

`\log (500)/((1)/(2))=\log (500\cdot2)=\log 1000.`

Now, notice that:

`1000=10^3\text{.}`

Therefore:

`\log 1000=3.`

Answer:

`\log 500-\log (1)/(2)=3.`