(a) In order to find the growth rate d, use the following formula:

where
P2 = 49000
P1 = 31000
t2 = 2018
t1 = 2014
Replace the previous values of the patameters into the formula for d:

Hence, the growth rate is $4500 per year.
(b) In order to write the store's sales as a linear model, use the following general equation for a line:

Replace the values of P1 and t1 and solve for P, as follow:

In this case we used t = 0 because we need a model to determine the store's sale from 2014 onward, which is equivalent that year 2014 is t = 0.
Hence, the linear model is
P(t) = 31000+4500t
(c) For 2025, t = 2025 - 2014 = 11, then, you have:

Hence, the stores's sale for 2025 will be $80500
(d) To determine the year when store's sales will exceed $105,000, replace P(t) = 105000 into the expression for P(t) and solve for t:

Consider that the counting is from 2014, then:
2014 + 16.4 = 2020.4
Which is equivalent to the year 2020.
Then, during the year 2020, we expect the store's sales exceed $105,000