Question

Find it's a y 30° 9 square root of 3

Answer 1

Let's use sin and cosine identities:

`\begin{gathered} \cos (\theta)=\frac{adjacent}{\text{hypotenuse}} \\ \\ \cos (30)=\frac{9\sqrt[]{3}}{y} \\ \\ \text{Solving for y:} \\ y=\frac{9\sqrt[]{3}}{\cos (30)}=18 \\ \end{gathered}`
`\begin{gathered} \sin (\theta)=\frac{opposite}{\text{hypotenuse}} \\ \\ \sin (30)=(x)/(18) \\ \text{Solving for x:} \\ x=18\cdot\sin (30)=9 \end{gathered}`