Matthew thought he could make 19free throws, but he only made 13.What was his percent error?

Question

asked Sep 28, 2023 224k views

1 Answer

Mathieu Urstein · Answer 1 · 2023-10-03T11:38:54+0000

Step-by-step explanation

Since he only made 13 from 19 throws, the percent error is as shown as follows:

$Percent\text{ error=}(\parallel measured-real\parallel)/(real)*100$

Plugging in the numbers into the expression:

$Percent\text{ error=}(\parallel19-13\parallel)/(13)*100$

Subtracting numbers:

$Percent\text{ error=}(6)/(13)*100$

Multiplying terms:

$Percent\text{ error=46.15\%}$

In conclusion, the percent error was 46.15%