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Which point lies on the line with a slope of m=9/10 that passes through the point (6,11)?(-2,4)(4,-2)(16,20)(20,16)

User Irisshpunk
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1 Answer

4 votes

Answer:

(16,20)

Step-by-step explanation:

First, we determine the equation of the line using the point-slope form.


y-y_1=m(x-x_1)

Slope, m=9/10

Therefore:


\begin{gathered} y-11=(9)/(10)(x-6) \\ 10(y-11)=9(x-6_{}) \\ 10y-110=9x-54 \\ 10y=9x-54+110 \\ 10y=9x+56 \end{gathered}

We then check the options. Anyone that satisfies the equation above is the required point.

Using the point (16,20)

When x=16 and y=20


\begin{gathered} 10(20)=9(16)+56 \\ 200=200 \end{gathered}

The point that passes through the line is (16,20).

Note: All the other points fail this test.

User HardikT
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