Question

Hello! I need some assistance with this homework question, pleaseQ4

Answer 1

Given the functions f(x) and g(x) defined as:

`\begin{gathered} f(x)=3x+5 \\ g(x)=5x-9 \end{gathered}`

(a)

We use the definition of the addition of two functions:

`(f+g)(x)=f(x)+g(x)`

Then:

`\begin{gathered} (f+g)(x)=3x+5+5x-9 \\ \Rightarrow(f+g)(x)=8x-4\ldots(1) \end{gathered}`

This is a polynomial, so the domain is x

(b)

Using the definition of subtraction of two functions:

`(f-g)(x)=f(x)-g(x)`

Then:

`\begin{gathered} (f-g)(x)=3x+5-5x+9 \\ \Rightarrow(f-g)(x)=-2x+14\ldots(2) \end{gathered}`

This is a polynomial, so the domain is x is any real number

(c)

We use the definition of the product between two functions:

`(f\cdot g)(x)=f(x)\cdot g(x)`

Then:

`\begin{gathered} (f\cdot g)(x)=(3x+5)\cdot(5x-9)=15x^2-27x+25x-45 \\ \Rightarrow(f\cdot g)(x)=15x^2-2x-45\ldots(3) \end{gathered}`

This is a polynomial, so the domain is x is any real number

(d)

We use the definition of the quotient between two functions:

`((f)/(g))(x)=(f(x))/(g(x))`

Then:

`((f)/(g))(x)=(3x+5)/(5x-9)\ldots(4)`

This is a rational expression, so the domain is the set of all the numbers such that the denominator is not 0. Finding those values:

`\begin{gathered} 5x-9=0 \\ \Rightarrow x=(9)/(5) \end{gathered}`

The domain is x

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