Question

I need help with this ( I also have to send another picture because of the answers that go with it)

Answer 1

Firstly, we should understand that we have right triangles inside the rectangle

These are BDC and ADC

a) Side DC

What we have is a rectangle and parallel sides are equal in length

AB = DC = 36

Thus, DC = 36

b) DA

At the four edges of the rectangle, we have right angles, which are 90 degrees

So, we can use Pythagoras' here

The square of the diagonal equals the sum of the squares of the two other sides

So we have;

`\begin{gathered} 39^2=36^2+DA^2 \\ DA^2\text{ = 225} \\ DA\text{ = }\sqrt[]{225} \\ DA\text{ = 15} \end{gathered}`

c) AC

Mathematically, the diagonals of a rectangle are congruent (equal in length) and they bisect each other

Thus, since BE is 19.5, BD is 2 * 19.5 = 39

AC = BD = 39

d) AE

AE is exactly same as BE which is 19.5

e) DE

DE is same as BE which is 19.5

f) Angle DAE

To get this, we consider triangle

g) Angle AEB

h) Angle ADC

This is part of the right angles; ADC is 90 degrees

i) BEC