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How many moles of solute are present in 1.5L of 0,28M NaSO?

How many moles of solute are present in 1.5L of 0,28M NaSO?-example-1
User AeyJey
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1 Answer

6 votes

Step-by-step explanation:

We are given: volume = 1.5 L

: concentration = 0.28 M

To find the number of moles, we use:

C = n/V

Where: C is concentration, n is number of moles, and V is volume

After rearranging:

n = CV

n = 0.28 * 1.5

n = 0.42 mol

Therefore, for a 1:1 reaction:

n of solute = 0.42 mol

User Hamid Parchami
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