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Consider the following equation of a circle what is the circle's center?

Consider the following equation of a circle what is the circle's center?-example-1
User Tashira
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1 Answer

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Recall that the radius-center form of the equation of a circle is as follows:


(x-h)^2+(y-k)^2=r^2,

where (h,k) is the circle's center, and r is its radius.

Therefore the center of the circle that represents the given equation is:


(1,(2)/(9)).

Answer:


(1,(2)/(9)).

User Mustansir Zia
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