Question

A water container at training is full and holds 5 liters of water . juan emptied 1 3/8 liters of the water into his drink bottle .crystal emptied 2 1/5 liters into her drink bottle after jose emptied some of water into his drink bottle there where 5/6 liters left in the original container. how much water did jose take?

Answer 1

Given:

Total amount of water = 5 liters

Amount used by Juan = 1⅜ liters

Amount used by Crystal = 2⅕ liters

Remaining amount of water = ⅚ liters

To find the amount of water used by Jose, use the formula:

Total Amount of water = Amount used by Juan + Amount used by Crystal + Amount used by Jose + remainder

Amount used by Jose = Total amount - (Amount used by Juan + Amount used by crystal + remainder)

Thus, we have:

`\text{ Amount used by Jose = }5\text{ - (1}(3)/(8)+2(1)/(5)+(5)/(6))`

Solving further:

`\begin{gathered} Amount\text{ used by Jose = 5 - (}(11)/(8)+(11)/(5)+(5)/(6)) \\ \\ \end{gathered}`
`\begin{gathered} \text{Amount used by Jose = }5\text{ - (}(165+264+100)/(120)) \\ \\ \text{Amount used by Jose = 5 - (}(529)/(120)) \\ \\ \end{gathered}`
`\begin{gathered} \text{Amount used by Jose = }(5)/(1)-(529)/(120)=(600-529)/(120)=(71)/(120) \\ \\ \end{gathered}`

ANSWER:

`(71)/(120)\text{ Liters}`

5