Answer:
To answer this we use the ideal gas equation:
![\begin{gathered} P.V=n.R.T \\ \\ T=(P.V)/(n.R) \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/6qd2s0b7d5663jjpljq6ws9i0b6c6hte39.png)
Where:
P is the pressure of the gas (2 atm)
V is the volume of the container (11L)
R is the ideal gas constant (0.0821 L.atm/K.mol)
T is the temperature of the gas
n is the number of moles.
To determine the number of moles we use the carbon dioxide molar mass (44 g/mol)
![n=(21g)/(44(g)/(mol))=0.477\text{ mol}](https://img.qammunity.org/2023/formulas/chemistry/college/mgyencetxn12xg4certbeottn49la0whk6.png)
Now we calculate:
![\begin{gathered} T=(2atm.11L)/(0.477mol.0.0821(L.atm)/(K.mol)) \\ \\ T=562\text{ K=289}\degree C \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/r3582g35c0ud7xe9k8mi8fusqicz5g9993.png)
So the answer is:
The temperature of the gas is 289°C