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Solve the following quadratic equationslelect the correct answer

User Anduplats
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1 Answer

4 votes

We have


\begin{gathered} (x+4)^2=25 \\ (x+4)^2-25=0 \end{gathered}

To find the roots of the equation (x+4)^2 must be equal to 25


\begin{gathered} (x+4)^2=25 \\ x+4=\sqrt[]{25} \\ x=\pm5-4 \\ x=-9\text{ and }x=1 \end{gathered}

So, the answer is letter C. x = -9 and x = 1.

User Lucas Azevedo
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