Question

Choose the rule that represents the series of transio1.A8()-(-1.5=5) (-y)-(1-12:5)D. (y) - (-+6-)8 (L.)-(:6-7)

Answer 1

We have:

A ( -3, 6 ) ; A' ( 3, -6 )

and

A (x,y) --> A' ( x + a, y + b )

So, A ( -3, 6 ) --> A' ( -3 + a, 6 + b ) or A ( -3, 6 ) --> A' ( 3, -6 )

Therefore:

`\begin{gathered} -3+a=3 \\ -3+a+3=3+3 \\ a=6 \end{gathered}`

and

`\begin{gathered} 6+b=-6 \\ 6+b-6=-6-6 \\ b=-12 \end{gathered}`

Answer: The rule is:

`(x,y)\rightarrow(x+6,y-12)`