Notice that for this question, they are providing you with:
1) The slope of the line (4)
2) a point on the plane through which the line goes (6, -2)
So you can directly use for this the "point-slope" form of a line which is as follows:
![y-y_0=m(x-x_(0))](https://img.qammunity.org/2023/formulas/mathematics/college/h7baguyvht9qadb6155yh3alfxqbl80msf.png)
This includes m as the slope, and the pair (x0, y0) as the pair representing the point the line goes through.
So, let's use the info they gave you to complete this:
![y-(-2)=4(x-6)](https://img.qammunity.org/2023/formulas/mathematics/college/zut4agmuvdbaillvvpylg8rhmrka1l5e5x.png)
which we can work out a little more:
![y+2=4x-24](https://img.qammunity.org/2023/formulas/mathematics/college/6bmub4nbpnoaufub8jaddpbwv3lcmf491h.png)
And even a little more to finish the equation of the line in its standard slope-intercept form:
![y=4x-24-2=4x-26](https://img.qammunity.org/2023/formulas/mathematics/college/tz9j20rxcjd8wbhuhq6dcyar3kthmkz2tm.png)
So the equation of the line is:
![y=4x-26](https://img.qammunity.org/2023/formulas/mathematics/college/x77c0mm159278umlsczk6jx0k7lmrqdas9.png)