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Write an equation of the line through (6,-2) with a slope of 4

User Ely
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Notice that for this question, they are providing you with:

1) The slope of the line (4)

2) a point on the plane through which the line goes (6, -2)

So you can directly use for this the "point-slope" form of a line which is as follows:


y-y_0=m(x-x_(0))

This includes m as the slope, and the pair (x0, y0) as the pair representing the point the line goes through.

So, let's use the info they gave you to complete this:


y-(-2)=4(x-6)

which we can work out a little more:


y+2=4x-24

And even a little more to finish the equation of the line in its standard slope-intercept form:


y=4x-24-2=4x-26

So the equation of the line is:


y=4x-26

User Andrei Matracaru
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