Let's begin by listing out the given information:
Let the initial location of the honeybee be represented as B
Let the location of the honeybee be represented as C
Let the location of the daffodil be represented as D
![\begin{gathered} BC(adjacent)=100m \\ \angle B=5^(\circ) \\ CD(opposite)=? \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/14351ji5hl9gf8lib2yauqukbc84tifdl7.png)
We will calculate for CD using the Trigonometric ratio (SOHCAHTOA). We will use TOA:
![\begin{gathered} Tan\theta=(opposite)/(adjacent)=(CD)/(BD) \\ \theta=5^(\circ),BD=100m \\ Tan5^(\circ)=(CD)/(100) \\ CD=100\cdot Tan5^(\circ) \\ CD=8.78\approx8.8 \\ CD=8.8m \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5cxmy6nj7xvs2vtudko3nyym9fi677lxsm.png)