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using the standard form, (MATH PROBLEM) of the group given quadratic equation, factor the left hand side of the equation into two linear factors

using the standard form, (MATH PROBLEM) of the group given quadratic equation, factor-example-1

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Factors are (6x-5) and (7x+1).

Given:

The quadratic equation is


42x^2=29x+5

The objective is to factor the equation.

The quadratic equation can be written as,


\begin{gathered} 42x^2=29x+5 \\ 42x^2-29x-5=0 \end{gathered}

On factorizing the above equation,


\begin{gathered} 42x^2+6x-35x-5=0 \\ 6x(7x+1)-5(7x+1)=0 \\ (6x-5)(7x+1)=0 \end{gathered}

Hence, the factors are (6x-5)(7x+1)=0.

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