Question

Tyrell was late for class 3 times in the month of June . Each time he was late he missed 5 and 1/2 minutes of class time . What is the total amount of class time Tyrell missed in the month of June ? A. 8 and 1/2 B . 15 minutes C . 16 and 1/2

Answer 1

Tyrell was late 3 times, each time he was late for 5 1/2 minutes, to determine how much time he missed in June, you have to multiply 5 1/2 by 3

`5(1)/(2)\cdot3`

First, express the mixed number as a fraction:

-Divide the whole number by 1 and add 1/2

`5(1)/(2)=(5)/(1)+(1)/(2)`

-Multiply the first fraction by 2, to express it as its equivalent with denominator 2, and add both fractions:

`(5\cdot2)/(1\cdot2)+(1)/(2)=(10)/(2)+(1)/(2)=(10+1)/(2)=(11)/(2)`

Multiply the result by 3

`(11)/(2)\cdot3=(11)/(2)\cdot(3)/(1)=(11\cdot3)/(2)=(33)/(2)`

Express the result as a mixed fraction:

Divide 33 by 2:

`33/2=16.2`

The whole number of the result is 16 and there are 0.5 remainings.

0.5 expressed as a fraction is 1/2.

So Tyrell missed 16 and 1/2 minutes in the month of June