Question

Someone please help me with example number two step-by-step full explanation and explain how to use the equation and how to rearrange it thanks

Answer 1

Given that the initial velocity is

`\begin{gathered} V_o=\text{ 2.7 km/h} \\ =2.7*(5)/(18) \\ =0.75\text{ m/s} \end{gathered}`

The acceleration is a = 0.40 m/s^2

The time is t = 3.6 s.

We have to find the final velocity, v.

The final velocity can be calculated by the formula

`V_f=V_o+at`

Substituting the values, the final velocity will be

`\begin{gathered} V_f=0.75+0.40*3.6 \\ =2.19\text{ m/s} \end{gathered}`

Thus, the final velocity is 2.19 m/s.