Question

The sum of 2 numbers is 96. the larger number is 9 less than 4 times the smaller. find boh nmbers.

Answer 1

The sum of 2 numbers is 96, this can be expressed as

`x+y=96`

The larger number is 9 less than 4 times the smaller, this can be expressed as

`x=4y-9`

Now, we replace the second equation in the first one

`\begin{gathered} 4y-9+y=96 \\ 5y=96+9 \\ y=(105)/(5) \\ y=21 \end{gathered}`

We use this number to find x.

`x=4\cdot21-9=84-9=75`

Hence, the numbers are 75 and 21.