GIVEN:
We are told that Jane wanted to buy a set of furniture for $1400. The terms are, 2-year loan at the rate of 18% per annum.
Required;
To determine how miuch her annual payment will be. Also, how much interest will she be paying?
Step-by-step solution;
We begin b y identifying the following;
![\begin{gathered} Principal=1400 \\ Rate(r)=0.18\text{ }(18\%) \\ Time(N)=2 \\ Period(K)=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/v31w1dmo30ephxjm0fnwjgcvdd437r3scc.png)
The monthly payment will now be determined by the formula below;
![P=(PMT(1-(1+(r)/(K))^(-N* K))/((r)/(K))](https://img.qammunity.org/2023/formulas/mathematics/college/99sjxql6m0wr1zq7lafjm6rox75mpabud6.png)
Now we substitute values;
![\begin{gathered} 1400=(PMT(1-(1+(0.18)/(12))^(-2*12))/((0.18)/(12)) \\ \\ 1400=(PMT(1-(1+0.015)^(-24))/(0.015) \\ \\ 1400=PMT(20.0304053663) \\ \\ (1400)/(20.0304053663)=PMT \\ \\ PMT=69.8937427575 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gaqekbibm4qr2adgztuc37lpyd1fgwrftw.png)
Therefore, the monthly payment will be $69.89 (approximately).
Therefore, annual payments will be;
![\begin{gathered} Annual\text{ }payment=69.89*12 \\ \\ Annual\text{ }payment=\text{\$}838.68 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/27blazbn39j17r8d5g6fr68c8tc8xlhqn2.png)
To determine her interest payment we calculate her total payments as follows;
![\begin{gathered} Total\text{ }payments=69.89*24 \\ \\ Total\text{ }payments=1677.36 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pphp1rnppz7fsea1ewgcteq1tw8ztaxj9c.png)
The interest payment therefore would be;
![\begin{gathered} Interest=Total\text{ }payment-Initial\text{ }amount \\ \\ Interest=1677.36-1400 \\ \\ Interest=277.36 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/861g9i20icd7vztv0c150kmgzo591pv11a.png)
Therefore;
ANSWER:
(a) Annual payment = $838.68
(b) Interest paid = $277.36