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Find the equation of the straight line passing through the point (-4,5) and perpendicular to the line y=2x+7.Suppose the equation is y=cx+d.Find c,d.

User Ij
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1 Answer

17 votes
17 votes

Answer:

The equation of the line is:


y = -(1)/(2)x + 3

Explanation:

Equation of a line:

The equation of a line has the following format:


y = mx + b

In which m is the slope and b is the y-intercept.

Perpendicular lines:

If two lines are perpendicular, this means that the multiplication of their slopes is -1.

Perpendicular to y=2x+7

This means that:


2m = -1


m = -(1)/(2)

So


y = -(1)/(2)x + b

Passing through the point (-4,5)

This means that when
x = -4, y = 5. We use this to find b.


y = -(1)/(2)x + b


5 = -(1)/(2)(-4) + b


2 + b = 5


b = 3

The equation of the line is:


y = -(1)/(2)x + 3

User Eudys
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