Question

A ladder leans against a building, making a 67 angle of elevation with the ground.The top of the ladder reaches a point on the building that is 29 feet above theground. To the nearest tenth of a foot, what is the distance between the base of thebuilding and the base of the ladder? Use the correct abbreviation for the units. If theanswer does not have a tenths place then include a zero so that it does.

Answer 1

`12.3ft`

1) The best way to tackle this question is by sketching out what's been given to us.

2) Note that the angle of elevation is found by the tangent. So let's apply this trig ratio:

`\begin{gathered} \tan(67)=(29)/(x) \\ \tan(67)x=29 \\ x=(29)/(\tan(67)) \\ x=12.30976\approx12.3ft \end{gathered}`

Hence, the ladder is 12.3 ft away from the base of the building