Question

A rectangular field has a length that is triple its width and a diagonal of 98 meter find the areaI need help, help me please

Answer 1

Data:

l = 3w

d = 98

To find the area, lets start drawing the field:

The area of rectangle is

`A=b\cdot h`

In this case

b = w

h= l = 3w

To determine the value of w, we can use the right triangle and the value of the diagonal that is the hypotenuse of the triangle. Then using Pythagoras theorem:

`w^2=d^2-(3w)^2`

We can clear the w from this equation:

`w^2=d^2-9w^2`
`w^2+9w^2=98^2`
`10w^2=98^2`
`w^2=(98^2)/(10)`
`w=\sqrt[]{(98^2)/(10)}=\sqrt[]{960.4}=30.99\approx40`

Now we know the value of w = 40

Then the area of the field is:
`A=w\cdot3w`
`A=40m\cdot3(40m)=4800m^2`