Question

What is the acceleration of the object at t = 2.5 s? (Indicate the direction with the sign of your answer.)________m/s^2

Answer 1

`\begin{equation*} -2.4\text{ m/s}^2 \end{equation*}`

Step-by-step explanation

To find the acceleration of the object at that time, we have to divide its velocity by the time:

`a=(v)/(t)`

The velocity of the object at t = 2.5s is 6 m/s. Therefore, the value of the object's acceleration at t = 2.5 s is:

`\begin{gathered} a=(6)/(2.5) \\ \\ a=2.4\text{ m/s}^2 \end{gathered}`

Notice from the graph that the velocity of the object is reducing in that time interval. This means that its acceleration has a negative value (deceleration).

Hence, the acceleration of the object at that time is:

`a=-2.4\text{ m/s}^2`