Question

MLG is a 30°-60°-90° triangle and LM= 40 in. Find GL.

Answer 1

To solve this, we can use the trigonometric function tangent.

`\tan \theta=(ol)/(al)`

Where ol is the length of the opposite leg to angle θ and al is the anjacent leg to angle θ.

By taking the tangent of the angle whose measure equals 30°, we get:

`\tan 30=(GL)/(LM)`

By solving for GL and replacing 40 for LM, we get:

`\begin{gathered} GL=LM*\tan 30 \\ GL=40*\tan 30 \\ GL=\frac{40\sqrt[]{3}}{3} \end{gathered}`

Then, the length of GL equals 40√3/3