Question

For problems 13-15, complete the chart below and then use the chart to determine the image points.90"(x, y) -(4-22,4)180°(x, y) - 42270"|(x,y) → (1,2-diy)13) Rotate 90" about the origin14) Rotate 180º about the origin15) Rotate 270" about the originM(3, 6) ► M'V(-5, -3) - VA(5, 3) AN(5, 10) - N'W/2. 1) - W'

Answer 1

Given a point (h,k), we can rotate it using the following formulas:

Rotate 90 degrees: (h,k) becomes (k,-h)

Rotate 180 degrees: (h,k) becomes (-h,-k)

Rotate 270 degrees: (h,k) becomes (k,-h)

In this case, we have (for the 90 degrees rotation):

`M(3,6)\text{ }\Rightarrow M^(\prime)(6,-3)\text{ }`

For the 180 degrees rotation:

`V(-5,-3)\Rightarrow V^(\prime)(5,3)`

And finally for the 270 degrees rotation:

`A(5,3)\text{ }\Rightarrow A^(\prime)(3,-5)`