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PS and PT are tangents to acircle, center O and radius10 cm, and meet at P. Thedistance PO = 26 cm.Calculate the perimeter ofthe quadrilateral PTOS.A.) 68 cmB.) 67.6 cmC.) 64 cmD.) 60 cm

PS and PT are tangents to acircle, center O and radius10 cm, and meet at P. Thedistance-example-1
User Vent
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1 Answer

1 vote

Answer:

A. 68cm

Step-by-step explanation:

PT and PS are tangents to circle O from point P.

Tangents to a circle from the same point are equal in length, therefore:


PT=PS

Next, the angle between the radius and tangent is 90 degrees.

Thus, triangle PTO is a right triangle with angle PTO=90 degrees.

Using Pythagoras theorem:


\begin{gathered} PO^2=PT^2+TO^2 \\ 26^2=PT^2+10^2 \\ PT^2=676-100 \\ PT^2=576 \\ PT=24\operatorname{cm} \end{gathered}

Therefore, the perimeter of PTOS:


\begin{gathered} \text{Perimeter}=PT+TO+OS+PS \\ =24+10+10+24 \\ =68\operatorname{cm} \end{gathered}

The correct choice is A.

Thus, triangle PTO is a right triangle with angle PTO=90 degrees

User Jannes
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