Question

A gas has a volume of 48.8 Liters at STP. what will it’s volume be at 14.0 atm and 25C

Answer 1

3.81L

Explanations:

According to the general gas equation

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where:

• P1 and P2 are the i,nitial and final pressure

,

• T1 and T2 are the ,initial and final temperature

,

• V1 and V2 are the ,initial and final volume

At standard temperature and pressure:

`\begin{gathered} P_1=1atm \\ T_1=0^0C=273K \end{gathered}`

Other parameters include

`\begin{gathered} V_1=48.8L \\ P_2=14.0atm \\ T_2=25^0C=25+273 \\ T_2=298K \end{gathered}`

Required

Final volume V2

Substitute the given parameters into the formula to have:

`\begin{gathered} V_2=(P_1V_1T_2)/(P_2T_1) \\ V_2=(1*48.8*298)/(14.0*273) \\ V_2=(14542.4)/(3822) \\ V_2=3.81L \end{gathered}`

Hence the final volume at 14.0atm and 25 degree celsius is 3.81L