Question

What is the area of the triangle? 10, 8, 12.8

Answer 1

Given, the sides of a triangle are 10, 8 and 12.8​.

Let, a=10, b=8 and c=12.8.

The semiperimeter of the triangle is,

`\begin{gathered} s=(a+b+c)/(2) \\ s=(10+8+12.8)/(2) \\ s=15.4 \end{gathered}`

Using Heron's formula, the area of the triangle is,

`A=\sqrt[]{s(s-a)(s-b)(s-c)}`
`\begin{gathered} A=√(15.4(15.4-10)(15.4-8)(15.4-12.8)) \\ A=√(15.4(5.4)(7.4)(2.6)) \\ A=\sqrt[]{1599.99} \\ A=40 \end{gathered}`

Therefore, the area of triangle is 40.