Question

In a cattle form of 10 cows and 5 pigs, two cattle are tested. What is the probability of choosing a cow and a pig for testing?10/5310/2110/10510/51

Answer 1

The Solution:

Given that:

Number of cows = 10

Number of pigs = 5

Total number of animals = 15

`\begin{gathered} Pr(\text{Cow)}=\frac{\text{ number of cows}}{\text{ Total number of animals}}=(10)/(15) \\ \\ Pr(Pig\text{)}=\frac{\text{ number of pigs}}{\text{ Total number of animals}}=(5)/(15) \end{gathered}`

We are required to find the probability of selecting a cow and a pig for testing.

`\begin{gathered} Pr(\text{Cow and Pig)=Pr(Cow and Pig) or Pr(Pig and Cow)} \\ =2*\text{ Pr(Cow and Pig)}=2*(10)/(15)*(5)/(14)=(10)/(3*7)=(10)/(21) \end{gathered}`

Therefore, the correct answer is [option 2]