201k views
3 votes
17. Calculate the number of moles of Al₂O₃ that are produced when 0.60 mol of Fe is produced in the following reaction.2 Al (s) + 3 FeO (s) -----> 3 Fe (s) + Al₂O₃ (s)a. 0.20 molb. 0.40 molc. 0.60 mold. 0.90 mol

1 Answer

4 votes

Step-by-step explanation:

Fe and Al2O3 are produced according to the following equation.

2 Al (s) + 3 FeO (s) -----> 3 Fe (s) + Al₂O₃ (s)

According to the coefficients of the reaction, when 3 moles of Fe are produced 1 mol of Al₂O₃ is also produced. So the molar ratio between Fe and Al₂O₃ is 3 to 1. We can use that ratio to find the number of moles of Al₂O₃ that are produced when 0.60 mol of Fe is produced.

3 mol of Fe : 1 mol of Al₂O₃ molar ratio

moles of Al₂O₃ = 0.60 mol of Fe * 1 mol of Al₂O₃/(3 mol of Fe)

moles of Al₂O₃ = 0.20 mol

Answer: a. 0.20 mol

User Nate Allen
by
3.5k points