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3 votes
What will be the force between a 2.80 * 10 ^ 3 object and a 9.75*10^ 10 kg asteroid when they are 28 m apart?

User Stamos
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1 Answer

3 votes
3 votes

The problem is about gravitational force, which means we have to use the universal law of gravitation.


F_(12)=G\cdot(m_1\cdot m_2)/(r^2_(12))

Where G = 6.67x10^-11, m1 = 2.80 * 10^3, m2 = 9.75*10^ 10, and r = 28m. Let's replace these values


\begin{gathered} F_(12)=6.61*10^(-11)N\cdot kg^(-2)m^2\cdot\frac{2.80*10^3\operatorname{kg}\cdot9.75*10^(10)\operatorname{kg}}{(28m)^2} \\ F_(12)=(180.453*10^2)/(780)N \\ F_(12)\approx23.2N \end{gathered}

Hence, the answer is C.

User Yuklia
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