let t be the tens digit of N
let u be the units digit of N
10t + u = N
10u + t = K
N - K > 18
(10t + u) - (10u + t) > 18
10t + u - 10u - t > 18
9t - 9u > 18
t - u > 2
t > u + 2
Since t < 10, it must be that u < 7
since N is odd the unit digits u = 1 , 3 , 5 ,...
If u = 1, t > 3, then N = 41 , 51 , 61 , 71 , 81 , 91.
If u = 3, t > 5, so N = 63 , 73 , 83 , 93.
If u = 5, t > 7, so N = 85 , 95.