The Solution.
Let the radius of the original circle be r.
By formula,

Taking the square root of both sides, we get
![r=\text{ }\sqrt[]{24}\text{ = 2mm}](https://img.qammunity.org/2023/formulas/mathematics/college/bjvrh7qoic7pa4rno5mlo2lxpk7ogevi6b.png)
For the new circle, the radius is multiplied by 5, that is,
![r=5r=5*2=10\operatorname{mm}]()
So, the area of the new circle is

Hence, the correct answer is 314 square mm.