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Write the equation of the line that passes through the point (4, 5) and is perpendicular to the graph of y = 2x – 3.

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Since it's perpendicular to y=2x-3 then the slope of the new line will be -1/2

then the equation in slope-point form is:


(y-5)=-(1)/(2)(x-4)

and solving for y, we have the equation in slope-intercept form:


y=-(1)/(2)x+7

User Hitesh Chavda
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