Question

34 ml of nitrogen occupies 15.0 ml under a pressure.928 atm at 25.0c what would be its volume at another time when the pressure was948 atm and the temperature 19.0c?

Answer 1

To solve this question, we simply need to use the combined gas equation which comprises of Boyle's law, Charles law and pressure law.

This formula is used to find the change of parameter of a gas from either one stage to another or to STP. Basically, it is used to compared or find missing values of gas since their equations are interconnected.

The combined gas equation is given as

`\frac{p_1v_1_{}}{t_1}=(p_2v_2)/(t_2)`

Now, let's defind our given parameters

`\begin{gathered} v_1=15mL \\ v_2=x \\ p_1=0.928\text{atm} \\ p_2=0.948atm_{} \\ t_1=25^0C=25+273.15=298.18K \\ t_2=19^0C=19+_{}273.15=292.15K \end{gathered}`

Now, we are seeking for the change in volume of the gas from 15ml to ?

V₂ is equal to

`\begin{gathered} (p_1v_1)/(t_1)=(p_2v_2)/(t_2) \\ v_2=(p_1v_1t_2)/(p_2t_1) \\ v_2=(0.928*292.15*15)/(0.948*298.15) \\ v_2=14.39mL \end{gathered}`

From the calculations above, the change of volume is equal to 14.39mL