The given system of equations is expressed as
4x + 2y = 8
16x - y = 14
To solve by elimination, we would make the coefficient of either variables to be equal in both equations. Let us make the coefficient of y to be equal by multiplying equation 2 by 2. It becomes
32x - 2y = 28
We would add the first equation to the third equation. It becomes
4x + 32x + 2y + - 2y = 8 + 28
4x + 32x + 2y - 2y = 8 + 28
36x = 36
x = 36/36
x = 1
Substituting x = 1 into the first equation, it becomes
4 * 1 + 2y = 8
4 + 2y = 8
2y = 8 - 4 = 4
y = 4/2
y = 2
The solutions are x = 1 and y = 2