Question

What is the length of a diagonal of an 18’ x 12’ rectangle

Answer 1

Step 1:

Draw the rectangle with the given dimensions

Step 2:

Next, apply the Pythagoras theorem

Opposite = 12

Adjacent = 18

Hypotenuse = L the side facing right angle

Step 3:

`\begin{gathered} \text{Pythagoras theorem} \\ \text{Opposite}^2+Adjacent^2=Hypotenuse^2 \\ 12^2+18^2=L^2 \\ 144+324=L^2 \\ 468=L^2 \\ L\text{ = }\sqrt[]{468} \\ \text{L = 6}\sqrt[]{13} \\ L\text{ = 21.6'} \end{gathered}`

Final answer

The length of the diagonal is 21.6