Question

Look at the activity series and select which two of the following reactionswould happen on their own. (Remember, if the lone element is more activethan the metal in the compound, the lone element will react and replace themetal in the compound.)The Activity SeriesMost ActiveLithium (LI)Potassium (K)Calcium (Ca)Sodium (Na)Aluminum (AI)Zinc (Zn)Iron (Fe)Tin (Sn)Lead (Pb)(Hydrogen) (H)Copper (Cu)Silver (Ag)Gold (Au)Least ActiveA. 3Ca + Al2O3 → 2Al + 3Cao-B. Sn + ZnSe SnSe + ZnO C. Al + 3LICI → AICI: + 3LIO D. 2Li + ZnBr2 → 2LiBr + Zn

Answer 1

Step 1

The activity series must be used to predict the reaction.

--------

Step 2

For the first reaction:

3Ca + Al2O3 → 2Al + 3CaO

This reaction happens (Activity of Ca > Activity of Al)

---------

Step 3

The second reaction:

Sn + ZnSe → SnSe + Zn

This reaction doesn't happen (Activity of Sn < Activity of Zn)

---------

Step 4

The third reaction:

Al + 3LiCI → AICI3 + 3Li

This reaction doesn't happen (Activity of Al < Activity of Li)

---------

Step 5

The fourth reaction:

2Li + ZnBr2 → 2LiBr + Zn

This reaction happens (Activity of Li > Activity of Zn)

----------------

Answer:

A. 3Ca + Al2O3 → 2Al + 3CaO

B. 2Li + ZnBr2 → 2LiBr + Zn