Question

Each individual letter of the word Wisconsin is placed on a piece of paper, and all 9 pieces of paper are placed in a hat. If one letter is selected at random from the hat, find the probability that a consonant is selected.P(consonant)-(Type a fraction. Simplify your answer.)

Answer 1

GIVEN:

We are told that all the individual letters of the word WISCONSIN are placed on a piece of paper. Then all nine pieces of paper are placed in a hat.

Required;

Find the probability that a letter chosen at random is a consonant.

Step-by-step solution;

The probability of an event is given by the formula;

`P[event]=\frac{number\text{ }of\text{ }required\text{ }outcomes}{number\text{ }of\text{ }all\text{ }possible\text{ }outcomes}`

The number of all possible outcomes is the total number of letters that stands a chance of being selected, and that is 9. The number of required outcomes for this experiment is 6 (that is, 6 consonants).

Therefore, the probability of selecting a consonant by random is;

`\begin{gathered} P[consonant]=(6)/(9) \\ \\ P[consonant]=(2)/(3) \end{gathered}`

ANSWER:

The probability of selecting a consonant is;

`P[consonant]=(2)/(3)`