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The question:6x - 15 ≥ 33

1 Answer

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To determine the possible values of x you have to isolate the x-term in one side of the inequality and the numbers on the other side.

The first step is to pass "-15" to the right side of the expression by applying the opposite operation to both sides of it, i.e. you have to add 15


\begin{gathered} 6x-15+15\ge33+15 \\ 6x\ge48 \end{gathered}

Then you have to divide both sides by 6 to determine the value of x:


\begin{gathered} (6x)/(6)\ge(48)/(6) \\ x\ge8 \end{gathered}

User TheEdgeOfRage
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