Let the shorter piece be called "x"
The longer piece is "3" less than TWICE shorter, so we can write the equation:
Longer is:
![2x-3](https://img.qammunity.org/2023/formulas/mathematics/high-school/li5cphmswye3wx0csj9l6g2jqayzsv987t.png)
Since the board is 12 feet, we can say:
Longer + Shorter = 12
we know longer = 2x - 3 and shorter is x, so we can write:
(2x - 3) + (x) = 12
We simply solve this equation for "x":
![\begin{gathered} 2x-3+x=12 \\ 3x-3=12 \\ 3x=12+3 \\ 3x=15 \\ x=(15)/(3) \\ x=5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x09c3ms4pp579higr611400z7c7as4ccgh.png)
So, shorter piece (x) is 5 feet
Longer piece, thus, is 12 - 5 = 7 feet