Question

what mass of co2 can be removed from the atmosphere by 454 g of lioh ?balanced formula :2LiOH ( s ) + CO2 ( g ) = Li2CO3 ( s ) + H2O ( l )

Answer 1

Approximately, 416 g of CO2 will be removed

Step-by-step explanation:

Here, we want to get the mass of LiOH that can be removed

We start by getting the number of moles of LiOH that wants to do the removal

We can get this by dividing the mass by the molar mass of LiOH

The molar mass of LiOH is 24 g/mol

Thus, we have the number of moles performing the removal as:

`(454)/(24)\text{ = 18.92 mol}`

Looking at the balanced equation, 2 moles of LiOH will remove 1 mole of Carbon iv oxide

What this means is that

18.92 moles LiOH will remove 18.92/2 = 9.46 moles

To get the actual mass removed, we multiply this number of moles by the molar mass of CO2

The molar mass of CO2 is 44g/mol

Thus, we have it that the mass removed will be:

`44\text{ }*\text{ 9.46 = 416.24 g}`

Approximately, 416 g of CO2 will be removed