The mass of rifle is M = 5kg . It fires the bullet of mass m =24 g = 0.024 kg
It travels a distance, d = 1.5 m and the time taken is t = 0.0023 s
The speed of the bullet will be
![\begin{gathered} v=(d)/(t) \\ =(1.5)/(0.0023) \\ =652.17\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/8fsrkjykks92l77wfjutegpb8867zuc5lu.png)
Let the recoil velocity be V. The initial velocity will be zero as rifle and bullet are at rest.
According to the conservation of momentum
![\begin{gathered} \text{Initial momentum = final momentum} \\ (M+m)*0=MV-mv\text{ } \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/vnja0kqy3r31jqqgm9dzz5rdn6pbsavb7r.png)
Here, rifle and bullet travel in opposite directions.
Substituting the values, the recoil velocity will be
![\begin{gathered} V=(mv)/(M) \\ =(0.024*652.17)/(5) \\ =3.13\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/6cd14uiadq8hgi3br6u77v3anwtpra6hmc.png)