Question

Using standard formation enthalpies, calculate the standard reaction enthalpy for this reaction. 6CO2(g) + 6H2O(l)C6H12O6 + 6O2(g) ANSWER: kJ/mol

Answer 1

2802.5 KJ/mol

Step-by-step explanation:

Calculate standard enthalpy of the Reaction :

6CO2(g) + 6H2O(l)C6H12O6 + 6O2(g)

using standard formation enthalpies . hence the standard enthalpy of the reaction = 2802.5 KJ/mol

attached below is the detailed solution